If This New Tech Works, You Won’t Need 32 Ether to Earn Staking Rewards

Blox, a non-custodial Ethereum 2.0 staking platform, is developing a solution that will allow users to pool their ether (ETH) cryptocurrency to get past the threshold required for staking when the upgraded network goes live.

  • The cryptocurrency accounting service provider announced on Wednesday that it is working alongside the Ethereum Foundation to develop “secret shared validator” nodes.
  • By creating a network of decentralized staking pools, Blox said it would allow users to aggregate their ETH and reach the required 32 ETH to stake on the network.
  • “Allowing ETH stakers to join the network and generate rewards with any amount of ETH is pivotal for making Eth 2.0 accessible for everyone,” said Blox’s CEO Alon Muroch.
  • Staking on Eth 2.0 requires a minimum of 32 ETH in order to participate and is expected to see an estimated 4.6%-10.3% rate of return on a user’s initial stake.
  • According to Blox, the entire
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Market Wrap: Bitcoin Surges on Square News to $10.9K; December Ether Options Pile Up

CoinDesk 20 Bitcoin Price Index

Bitcoin is flashing green as Square converts some of its cash to crypto while ether options traders are making lots of bets for December expiration.

  • Bitcoin (BTC) trading around $10,890 as of 20:00 UTC (4 p.m. ET). Gaining 2.1% over the previous 24 hours.
  • Bitcoin’s 24-hour range: $10,532-$10,962
  • BTC above its 10-day and 50-day moving averages, a bullish signal for market technicians.

Bitcoin’s price popped Thursday, led higher almost immediately following the announcement that payments firm Square had invested $50 million to purchase 4,709 BTC. The development pushed the price per 1 BTC to as high as $10,962 before settling to $10,890 as of press time. 

Read More: Square Puts 1% of Total Assets in Bitcoin in Surprise $50M Investment

Related: The Market Reacts to Square’s $50M Bitcoin Buy

“News that Jack Dorsey’s Square has purchased about $50 million worth of bitcoin is a definite positive that appears to have

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